4y^2+2y+1=0

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Solution for 4y^2+2y+1=0 equation: 



4y^2+2y+1=0

a = 4; b = 2; c = +1;
Δ = b2-4ac
Δ = 22-4·4·1
Δ = -12
Delta is less than zero, so there is no solution for the equation

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